To investigate the effect of surface area on the rate of reaction using the enzyme Catalase, found in potato, and the substrate Hydrogen Peroxide.
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ESSAY DETAILS
Words: 521
Pages: 2
(approximately 235 words/page)
Pages: 2
(approximately 235 words/page)
Essay Database > Social Sciences > Philosophy
Hydrogen peroxide has an acidic pH which will break down into water which has a neutral pH. This may effect the enzyme action as many enzymes work faster in a neutral environment, the only control over this is the fact that it will happen in each test and to consider its effect at the end of the experiment. I will need to use the same potato and cut a fresh chip at each stage of
showed first 75 words of 521 total
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showed first 75 words of 521 total
showed last 75 words of 521 total
Each rounded to a whole number r = 5mm d = 10mm l = 40mm p = 3.14... New surface area exposed by each cut = 157.1mm2 2pr2 + 2rl (+2pr2) (+2pr2).... 1st chip formula = 2pr2 + 2rl = 2p25+400 = 1414mm2 2nd chip formula = 1st chip surface area + 2pr2 = 1414mm2 + 157.1= 1571 mm2 3rd chip formula = 2nd chip surface area + 2pr2 = 1571+ 157.1 = 1728 mm2 4th chip formula = 3rd chip surface area + 2pr2 = 1728 + 157.1 = 1885 mm2 5th chip formula = 4th chip surface area + 2pr2 = 1885 + 157.1 = 2042 mm2 6th chip formula = 5th chip surface ...
Each rounded to a whole number r = 5mm d = 10mm l = 40mm p = 3.14... New surface area exposed by each cut = 157.1mm2 2pr2 + 2rl (+2pr2) (+2pr2).... 1st chip formula = 2pr2 + 2rl = 2p25+400 = 1414mm2 2nd chip formula = 1st chip surface area + 2pr2 = 1414mm2 + 157.1= 1571 mm2 3rd chip formula = 2nd chip surface area + 2pr2 = 1571+ 157.1 = 1728 mm2 4th chip formula = 3rd chip surface area + 2pr2 = 1728 + 157.1 = 1885 mm2 5th chip formula = 4th chip surface area + 2pr2 = 1885 + 157.1 = 2042 mm2 6th chip formula = 5th chip surface ...