Pythagoras' Theorem.

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…substitute 'n' with 'a'. The formula for 'n' is: 'n = a - 4'. 2 'b = a2 - 1' 4 I got this by knowing that n2 + 4n +3 can be factorised as (n + 1)(n + 3) so using 'a' instead, factorised, it looks like this: (a - 4 - 1)(a - 4 + 1) 2 2 'c = a2 + 1' 4 I got this by just adding 2 onto the formula for 'b'. L is always larger than k 2lk l2-k2 l2+k2